Can you run in localhost an app that use Twitter OAuth? – Stack Overflow

Can you run in localhost an app that use Twitter OAuth? – Stack Overflow

Can you run in localhost an app that use Twitter OAuth? – Stack Overflow



https://bugs.php.net/bug.php?id=46246 에서 참조



Description: ------------ There is a difference in behavior of call_user_func(array($this, $method)) and $this->$method() while class B inherits from class A and both declares the same method. The call_user_func() function seems to work as expected, but using $this->$method() seems to invoke parent method implementation instead of the overridden one. Reproduce code: --------------- class A { protected function Test() { echo 'Hello from '.get_class($this); } public function call($method, $args = array()) { return $this->$method(); //return call_user_func(array($this, $method)); } } class B extends A { protected function Test() { echo 'Overridden hello from '.get_class($this); } } $a = new A; $b = new B; $a->call('Test'); $b->call('Test'); Expected result: ---------------- Hello from A Overridden hello from B Actual result: -------------- Hello from A Hello from B


https://bugs.php.net/bug.php?id=46246 에서 참조



Description: ------------ There is a difference in behavior of call_user_func(array($this, $method)) and $this->$method() while class B inherits from class A and both declares the same method. The call_user_func() function seems to work as expected, but using $this->$method() seems to invoke parent method implementation instead of the overridden one. Reproduce code: --------------- class A { protected function Test() { echo 'Hello from '.get_class($this); } public function call($method, $args = array()) { return $this->$method(); //return call_user_func(array($this, $method)); } } class B extends A { protected function Test() { echo 'Overridden hello from '.get_class($this); } } $a = new A; $b = new B; $a->call('Test'); $b->call('Test'); Expected result: ---------------- Hello from A Overridden hello from B Actual result: -------------- Hello from A Hello from B


https://bugs.php.net/bug.php?id=46246 에서 참조



Description: ------------ There is a difference in behavior of call_user_func(array($this, $method)) and $this->$method() while class B inherits from class A and both declares the same method. The call_user_func() function seems to work as expected, but using $this->$method() seems to invoke parent method implementation instead of the overridden one. Reproduce code: --------------- class A { protected function Test() { echo 'Hello from '.get_class($this); } public function call($method, $args = array()) { return $this->$method(); //return call_user_func(array($this, $method)); } } class B extends A { protected function Test() { echo 'Overridden hello from '.get_class($this); } } $a = new A; $b = new B; $a->call('Test'); $b->call('Test'); Expected result: ---------------- Hello from A Overridden hello from B Actual result: -------------- Hello from A Hello from B

__call()

The call() magic function is to class functions what __get() is to class variables – if you call meow() on an object of class dog, PHP will fail to find the function and check whether you have defined a __call() function. If so, your __call() is used, with the name of the function you tried to call and the parameters you passed being passed in as parameters one and two respectively.

Here’s an example of __call() in action:

<?php
    
class dog {
        public $Name;

        public function bark() {
            print "Woof!n";
        }

        // public function meow() {
            // print "Dogs don't meow!n";
        // }

        public function __call($function, $args) {
            $args = implode(', ', $args);
            print "Call to $function() with args '$args' failed!n";
        }
    }

    $poppy = new dog;
    $poppy->meow("foo", "bar", "baz");
?>

Again, note that the meow() function is commented out – if you want to be sure that __call() is not used if the function already exists, remove the comments from meow().